How many grams of K2O can be made from 43 g of potassium and 32 g of oxygen from the following equation? 4K + 02 –> 2

Question

How many grams of K2O can be made from 43 g of potassium and 32 g of oxygen from the following
equation?
4K + 02 –> 2K2O

in progress 0
Bình An 3 years 2021-08-30T01:16:46+00:00 1 Answers 13 views 0

Answers ( )

    0
    2021-08-30T01:18:37+00:00

    Answer:

    51.81g of K2O are produced

    Explanation:

    Based on the reaction, 4 moles of K reacts per mole of oxygen to produce 2 moles of K2O. To solve this question we must find the moles of each reactant in order to find the limiting reactant. With limiting reactant we can find the moles of K2O produced and its mass:

    Moles K -Molar mass: 39.0983g/mol-

    43g * (1mol / 39.0983g) = 1.1 moles K

    Moles O₂ -Molar mass: 32g/mol-

    32g * (1mol / 32g) = 1mol O₂

    The moles required for the reaction of 1 mole of O₂ are 4 moles of K. As there are just 1.1 moles, K is the limiting reactant.

    The moles and the mass of K2O produced are:

    1.1moles K * (2mol K2O / 4mol K) = 0.55 moles K

    Molar mass K2O = 94.2g/mol

    0.55 moles K * (94.2g / mol) =

    51.81g of K2O are produced

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )