How many grams of ethanol, C2H5OH, can be boiled with 843.2 kJ of heat energy? The molar heat of vaporization of ethanol is 38.6 kJ/mol.

Question

How many grams of ethanol, C2H5OH, can be boiled with 843.2 kJ of heat energy? The molar heat of vaporization of ethanol is 38.6 kJ/mol.

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Thông Đạt 3 years 2021-08-23T12:42:46+00:00 1 Answers 22 views 0

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    2021-08-23T12:44:23+00:00

    Answer:

    1.00 × 10³ g

    Explanation:

    Step 1: Given data

    • Provided heat (Q): 843.2 kJ
    • Molar heat of vaporization of ethanol (ΔH°vap): 38.6 kJ/mol

    Step 2: Calculate the moles of ethanol vaporized

    Vaporization is the passage of a substance from liquid to gas. We can calculate the number of moles (n) vaporized using the following expression.

    Q = ΔH°vap × n

    n = Q / ΔH°vap

    n = 843.2 kJ / (38.6 kJ/mol) = 21.8 mol

    Step 3: Calculate the mass corresponding to 21.8 moles of ethanol

    The molar mass of ethanol is 46.07 g/mol.

    21.8 mol × 46.07 g/mol = 1.00 × 10³ g

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