How many grams of Br are in 345g of CaBr2?

Question

How many grams of Br are in 345g of CaBr2?

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RuslanHeatt 5 years 2021-07-13T09:01:56+00:00 1 Answers 41 views 0

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  1. Neala
    0
    2021-07-13T09:03:03+00:00
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    Answer:

    276g of Br are present

    Explanation:

    To solve this question we need to find the moles of CaBr2 using its molar mass -CaBr2: 199.89g/mol-. As 1 mole of CaBr2 contains 2 moles of Br we can find the moles of Br and its mass:

    Moles CaBr2:

    345g * (1mol/199.89g) = 1.7259 moles CaBr2

    Moles Br:

    1.7259 moles CaBr2 * (2mol Br / 1mol CaBr2) = 3.4519 moles Br

    Mass Br -Molar mass: 79.904g/mol-

    3.4519 moles Br * (79.904g/mol) = 276g of Br are present

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )