High speed stroboscopic photographs show that the head of a 244 g golf club is traveling at 57.6 m/s just before it strikes a 45.2 g golf ba

Question

High speed stroboscopic photographs show that the head of a 244 g golf club is traveling at 57.6 m/s just before it strikes a 45.2 g golf ball at rest on a tee. After the collision, the club head travels (in the same direction) at 39.9 m/s. Find the speed of the golf ball just after impact.

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Eirian 4 years 2021-09-02T21:05:23+00:00 1 Answers 77 views 0

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    2021-09-02T21:07:17+00:00

    Answer:

    The speed will be “1.06 m/s“.

    Explanation:

    The given values are:

    Momentum,

    m1 = 244 g

    m2 = 45.2 g

    On applying momentum conservation
    ,

    Let v2 become the final golf’s speed.  

    From Momentum Conservation

    ⇒  Total \ initial \ momentum = Total \ final \ momentum

    ⇒  m1\times u1 + m2\times u2 = m1\times v1 + m2\times v2

    On putting the estimated values, we get

    ⇒  0.244\times 57.6+0=0.244\times 39.9+45.2\times v2

    ⇒  57.844+0=9.7356+45.2\times v2

    ⇒  48.1084=45.2\times v2

    ⇒  v2=\frac{48.1084}{45.2}

    ⇒  v2=1.06 \ m/s

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