HELP PLEASE!! A 41kg girl sits on the edge of a merry-go-round. If she travels at 0.02ms and the radius of her motion is 2.1m, what i

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HELP PLEASE!!
A 41kg girl sits on the edge of a merry-go-round. If she travels at 0.02ms and the radius of her motion is 2.1m, what is the centripetal force acting upon her?

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1 year 2021-09-03T02:34:24+00:00 1 Answers 4 views 0

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    2021-09-03T02:36:12+00:00

    Answer:

    m=41 kg

    v=0,02 ms

    R=2,1 m

    F-?

    a=v²/R

    a=(0,02) ²/2,1=0,0002

    F=m*a

    F=41*0,0002=0,0082 H

    F=0,0082 H

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