Help meeeee cứuu vs ạ Question Help meeeee cứuu vs ạ in progress 0 Môn Toán Eirian 4 years 2020-10-28T22:05:23+00:00 2020-10-28T22:05:23+00:00 1 Answers 65 views 0
Answers ( )
`a) (2x + 1)(x² + x + 1)(2x² – 3x + 1) = 0}`
`=>` \(\left[ \begin{array}{l}2x + 1 = 0\\x² + x + 1 = 0 (l)\\2x² – 3x + 1 = 0\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x = -\dfrac{1}{2}\\x = 1\\x = \dfrac{1}{2}\end{array} \right.\)
`=> A = {±(1)/2; 1}`
`b) 6x² – 5x + 1 = 0`
`<=>` \(\left[ \begin{array}{l}x = \dfrac{1}{2}\\x = \dfrac{1}{3}\end{array} \right.\)
Mà: `x ∈ ZZ`
`=> B = ∅`
`c) (2x + x²)(x² + x – 2)(x² – x – 12) = 0`
`<=>` \(\left[ \begin{array}{l}2x + x² = 0\\x² + x – 2 = 0\\x² – x – 12 = 0\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x = 0\\x = -2\\x = 1\\ x = -2\\x = 4\\x = -3\end{array} \right.\)
Mà: `x ∈ NN`
`=> C = {0; 1; 4}`
`d) x² – 9 = 0`
`<=> x = ±3`
`=> G = {±3}`