HELP A movie theater is arranged with 7 seats in the front row, 12 seats in the middle row, and 11 seats in the back row. People enter

Question

HELP
A movie theater is arranged with 7 seats in the front row, 12 seats in the middle row, and 11 seats in the back row. People enter the movie theater and randomly sits in different spots. What is the probability that the first person who enters the theater will be in the middle row?

type in your fraction answers as a/b

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King 5 years 2021-07-22T16:19:51+00:00 1 Answers 23 views 0

Answers ( )

  1. Nho
    0
    2021-07-22T16:21:36+00:00
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    Answer:P=\frac{2}{5}

    Step-by-step explanation:

    Given

    A movie theater has 7 seats in the front row  

    12 seats in the middle row

    11 seats in the back row

    Probability first person who enters the theater will be in the middle row

    P=\frac{\text{No. of middle seats}}{\text{total seats}}

    P=\frac{12}{7+12+11}=\frac{12}{30}

    P=\frac{2}{5}

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