h(x) = x^2 + 2x – 24 / x^2 + 10x + 25 Describe the behavior of the function h around its vertical asymptote at x = -5 ​

Question

h(x) = x^2 + 2x – 24 / x^2 + 10x + 25 Describe the behavior of the function h around its vertical asymptote at x = -5 ​

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Euphemia 6 months 2021-07-30T07:49:26+00:00 1 Answers 9 views 0

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  1. linhdan
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    2021-07-30T07:50:58+00:00
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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )