Given the line y =2/3x-3 Write the equation of a line perpendicular to it that passes through the point (4, -1)

Question

Given the line y =2/3x-3
Write the equation of a line perpendicular to it that passes
through the point (4, -1)

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Thái Dương 3 years 2021-08-02T01:15:54+00:00 1 Answers 9 views 0

Answers ( )

  1. thienthanh
    0
    2021-08-02T01:17:29+00:00
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    Answer:

    y= -3/2x + 5

    Step-by-step explanation:

    You do the opposite reciprocal of the original equation’s slope.

    Then you use the new slope from the point (4,-1) on the graph to find the y-intercept. Which is (0,5).

    That gets your answer of -3/2x + 5.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )