Given that the acceleration of gravity at the surface of Mars is0.38 of what it is one Earth, and that Mars’ radius is 3400 km,determine the

Question

Given that the acceleration of gravity at the surface of Mars is0.38 of what it is one Earth, and that Mars’ radius is 3400 km,determine the mass of Mars.

in progress 0
Vodka 5 months 2021-09-05T08:55:37+00:00 1 Answers 0 views 0

Answers ( )

  1. mocmien2
    0
    2021-09-05T08:57:22+00:00
    Reply

    Answer:

    1.156\times 10^{24}\ kg

    Explanation:

    Given:

    Gravity of Mars = 0.38 times the gravity at Earth

    Gravity of Earth is, g_{Earth}=9.8\ m/s^2

    Radius of Mars (R) = 3400 km

    Mass of mars (M) = ?

    We know that, the acceleration due to gravity  of a planet of mass ‘M’ and radius ‘R’ is given as:

    g=\dfrac{GM}{R^2}

    Now, as per question:

    g_{Mars}=0.68g_{Earth}

    Plug in 9.8 for g_{Earth} and solve for g_{Mars}. This gives,

    g_{Mars}=0.68\times 9.8=6.67\ m/s^2

    Now, plug in this value in the above equation and solve for ‘M’. This gives,

    6.67=\frac{6.67\times 10^{-11}M}{(3400\times 10^3)^2}\\\\1.156\times 10^{13}=10^{-11}M\\\\M=\frac{1.156\times 10^{13}}{10^{-11}}\\\\M=1.156\times 10^{24}\ kg

    Therefore, the mass of Mars is 1.156\times 10^{24}\ kg.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )