Given that 4704/m = n^2, where m and n are whole numbers and n is as large as possible, find the value of m and of n

Question

Given that 4704/m = n^2, where m and n are whole numbers and n is as large as possible, find the value of m and of n

in progress 0
Lệ Thu 3 years 2021-08-12T19:14:02+00:00 1 Answers 143 views 0

Answers ( )

  1. Philomena
    0
    2021-08-12T19:15:31+00:00
    Reply

    Answer:

    n=28,m=6

    Step-by-step explanation:

    Rearrange to give 4704 = m * n^2

    Express 4704 in its prime factorisation:

    2^5 * 3^1 * 7^2

    We know that n must be as large as possible and, because it is squared, be the even numbers.

    We get n^2 = 2^4 * 7^2 so n = 2^2*7 = 28

    m is the leftovers

    2^1*3 = 6

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )