Hưng Gia 90 Questions 546 Answers 0 Best Answers 20 Points View Profile0 Hưng Gia Asked: October 13, 20202020-10-13T12:38:48+00:00 2020-10-13T12:38:48+00:00In: Môn ToánGiúp mình với mọi người ơi Tìm x, biết:0Giúp mình với mọi người ơi Tìm x, biết: ShareFacebookRelated Questions a 5^n=125 ... Giúp mình vs ạ. Mình gấp lắm. Lm hộ mình với mình ko lm đc2 AnswersOldestVotedRecentHưng Khoa 176 Questions 850 Answers 0 Best Answers 20 Points View Profile dangkhoa 2020-10-13T12:40:09+00:00Added an answer on October 13, 2020 at 12:40 pm $\sqrt[]{x^{2}+x+1}=x+2$⇒$x^{2}$+x+1=$(x+2)^{2}$⇔$x^2$+x+1=$x^{2}$+4x+4⇔3x+3=0⇔x=-10Reply Share ShareShare on FacebookEuphemia 193 Questions 788 Answers 0 Best Answers 20 Points View Profile Euphemia 2020-10-13T12:40:21+00:00Added an answer on October 13, 2020 at 12:40 pm `\sqrt(x^2+x+1)=x+2``⇒\sqrt(x^2+x+1)^2=(x+2)^2``⇒x^2+x+1=x^2+4x+4``⇒3x+3=0``⇒x=-1`Vậy `x=-1` 0Reply Share ShareShare on FacebookLeave an answerLeave an answerCancel reply By answering, you agree to the Terms of Service and Privacy Policy .* Save my name, email, and website in this browser for the next time I comment.
Hưng Khoa
$\sqrt[]{x^{2}+x+1}=x+2$
⇒$x^{2}$+x+1=$(x+2)^{2}$
⇔$x^2$+x+1=$x^{2}$+4x+4
⇔3x+3=0
⇔x=-1
Euphemia
`\sqrt(x^2+x+1)=x+2`
`⇒\sqrt(x^2+x+1)^2=(x+2)^2`
`⇒x^2+x+1=x^2+4x+4`
`⇒3x+3=0`
`⇒x=-1`
Vậy `x=-1`