Giúp mình với, mình cảm ơn

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Giúp mình với, mình cảm ơn
giup-minh-voi-minh-cam-on

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Xavia 5 years 2021-05-21T06:30:23+00:00 1 Answers 23 views 0

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  1. Jezebel
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    2021-05-21T06:31:44+00:00
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    a,

    $y=2x^4-\dfrac{1}{3}x^3-\dfrac{1}{2}x^2+\sqrt{x}+5$

    $y’=2(x^4)’-\dfrac{1}{3}(x^3)’-\dfrac{1}{2}(x^2)’+(\sqrt{x})’+(5)’$

    $=2.4x^3-\dfrac{1}{3}.3x^2-\dfrac{1}{2}.2x+\dfrac{1}{2\sqrt{x}}+0$

    $=8x^3-x^2-x+\dfrac{1}{2\sqrt{x}}$

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