Giúp mình với ạ mai nộp rồi <3 Question Giúp mình với ạ mai nộp rồi <3 in progress 0 Môn Toán Sigridomena 6 years 2020-10-14T00:57:32+00:00 2020-10-14T00:57:32+00:00 1 Answers 110 views 0
Answers ( )
(2x-5)^2-(x+1)^2=0
[(2x-5)+(x+1)].[(2x-5)-(x+1)]=0
(2x-5)+(x+1).(2x-5)-(x+1) =0
(2x-5)^2 =0
2x-5 =0
2x=0+5
2x=5
x=5:2
x=5/2
(5x-4)^2-49x^2=0
[(5x-4)+7x].[(5x-4)-7x]=0
(5x-4)+7x.(5x-4)-7x=0
(5x-4)^2=0
5x-4=0
5x=4
x=4:5
x=4/5