giúp mình nha gggg Question giúp mình nha gggg in progress 0 Môn Toán Tryphena 5 years 2021-05-20T17:24:41+00:00 2021-05-20T17:24:41+00:00 2 Answers 31 views 0
Answers ( )
Đặt `B= 29/1 + 28/2 +27/3+…+2/28 + 1/29`
`B= (28/2+1) + (27/3+1)+…+(1/29 +1) + (29/1+1)`
`B= 30/2 + 30/3 +…+30/29 + 30/30`
`B= 30(1/2 +1/3+…+1/29+1/30)`
=> `A = (30(1/2+1/3+…+1/29+1/30))/(1/2+1/3+1/4+…+1/30)`
=> `A= 30`
Vậy `A=30`
Giải thích các bước giải:
$ A=\dfrac{ \dfrac{29}{1} + \dfrac{28}{2} + \dfrac{27}{3} + … + \dfrac{3}{27} + \dfrac{2}{28} + \dfrac{1}{29}} { \dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+…+\dfrac{1}{29}+\dfrac{1}{30}}$
$\\$
Đặt `B = 29/1 + 28/2 + 27/3 + … + 3/27 + 2/28 + 1/29`
`=> B = (28/2 + 1 ) + (27/3+ 1 ) + … + (3/27+ 1 ) + (2/28+ 1 ) + (1/29+ 1 ) + 1 `
`=> B = 30/2 + 30/3 + … + 30/27 + 30/28 + 30/29 + 30/30`
`=> B = 30. ( 1/2 + 1/3 + … + 1/27 + 1/28 + 1/29 + 1/30)`
$\\$
Vậy `A`=$\dfrac{ 30.(\dfrac{1}{2}+\dfrac{1}{3}+…+\dfrac{1}{28}+\dfrac{1}{29}+\dfrac{1}{30})} { \dfrac{1}{2}+\dfrac{1}{3}+….+\dfrac{1}{29}+\dfrac{1}{30}}$ `= 30`