giải hộ mình với ạ,,,,

Question

giải hộ mình với ạ,,,,
giai-ho-minh-voi-a

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Jezebel 5 years 2021-05-16T17:22:02+00:00 2 Answers 24 views 0

Answers ( )

  1. Adela
    0
    2021-05-16T17:23:24+00:00
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    `a) P(x) + Q(x) = (-5x^4 + 7x^3 -3x^2 -5-2x) + (3x-4x^4 + 6x^3-1)`
    ` = -5x^4 + 7x^3 -3x^2 -5-2x + 3x-4x^4 + 6x^3-1`
    ` = (-5x^4 – 4x^4)+(7x^3 + 6x^3) – 3x^2 – (2x-3x) – (5+1)`
    ` = -9x^4 + 13x^3 -3x^2 + x -6`

    `b) P(x) – Q(x) = (-5x^4 + 7x^3 -3x^2 -5-2x) – (3x-4x^4 + 6x^3-1)`
    ` = -5x^4 + 7x^3 -3x^2 -5-2x – 3x+ 4x^4 – 6x^3+1`
    ` =(-5x^4 + 4x^4) + (7x^3 – 6x^3) -3x^2 + (-2x-3x) + (-5+1)`
    ` = -x^4 + x^3 -3x^2 -5x – 4`

  2. linhdan
    0
    2021-05-16T17:23:49+00:00
    Reply

    \[●\]Đáp án+Giải thích các bước giải:

    \[a) P(x) + Q(x) = (-5x^4 + 7x^3 -3x^2 -5-2x) + (3x-4x^4 + 6x^3-1)\\= -5x^4 + 7x^3 -3x^2 -5-2x + 3x-4x^4 + 6x^3-1\\= -9x^4 + 13x^3 -3x^2 + x -6\\b) P(x) – Q(x) = (-5x^4 + 7x^3 -3x^2 -5-2x) – (3x-4x^4 + 6x^3-1)\\= -5x^4 + 7x^3 -3x^2 -5-2x – 3x+ 4x^4 – 6x^3+1\\= -x^4 + x^3 -3x^2 -5x – 4\]

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