g n diffraction, the formula for minima is given by a times s i n (theta )equals m lambda, where a is the width of the slit, theta is the an

Question

g n diffraction, the formula for minima is given by a times s i n (theta )equals m lambda, where a is the width of the slit, theta is the angle of dispersion, m is the order, and lambda is the wavelength. For a wavelength of 630 nm, m equals 3, and a equals 5 times 10 to the power of negative 6 end exponent m. Calculate the angular spread in Degrees. Enter only the numerical value (i.e. omit the unit abbreviations when inputting your answer into Blackboard).

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Kim Cúc 3 years 2021-09-05T00:15:38+00:00 1 Answers 12 views 0

Answers ( )

  1. danthu
    0
    2021-09-05T00:17:32+00:00
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    Answer:

    θ = 22.2

    Explanation:

    This is a diffraction exercise

            a sin θ = m λ

    The extension of the third zero is requested (m = 3)

    They indicate the wavelength  λ = 630 nm = 630 10⁻⁹ m and the width of the slit  a = 5 10⁻⁶ m

             sin  θ = m λ / a

             sin  θ = 3 630 10⁻⁹ / 5 10⁻⁶

             sin  θ = 3.78 10⁻¹ = 0.378

              θ = sin⁻¹  0.378

             

    to better see the result let’s find the angle in radians

              θ = 0.3876 rad

    let’s reduce to degrees

             θ = 0.3876 rad (180º /π rad)

             θ = 22.2º

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