g A car with a mass of 1,120.0 kg accelerates from 0 to 80.0 km/h in 10.0 s. The driver applies the brakes when the car is moving at 80.0 km

Question

g A car with a mass of 1,120.0 kg accelerates from 0 to 80.0 km/h in 10.0 s. The driver applies the brakes when the car is moving at 80.0 km/h, and the car comes to rest after traveling 44.0 m. What is the net force (in N) on the car during its deceleration

in progress 0
Thu Hương 5 years 2021-07-21T05:56:08+00:00 1 Answers 24 views 0

Answers ( )

  1. Verity
    0
    2021-07-21T05:57:47+00:00
    Reply

    Answer:

    8761.5 N

    Explanation: Given that a car with a mass of 1,120.0 kg accelerates from 0 to 80.0 km/h in 10.0 s. The driver applies the brakes when the car is moving at 80.0 km/h, and the car comes to rest after traveling 44.0 m. What is the net force (in N) on the car during its deceleration

    Mass m = 1120kg

    First change km/h to m/s

    (80 × 1000) ÷ 3600

    Velocity = 22.2 m/s

    Acceleration = ( 22.2 – 0 ) ÷ 10

    Acceleration = 2.2 m/s^2

    Force F1 = mass × acceleration

    Substitutes all the parameters into the formula

    F1 = 1120 × 2.2

    F1 = 2489 N

    For the car to come to rest, it will be decelerating.

    Using 3rd law of motion

    V^2 = U^2 + 2as

    V = 0 since it is coming to rest.

    Substitute all the parameters into the formula

    0 = 22.2^2 – 2 × a × 44

    88a = 492.84

    a = 492.84/88

    a = 5.6 m/s^2

    The force F2 = 1120 × 5.6

    F2 = 6272.5N

    Net force = 6272.5 + 2489

    Net force = 8761.5 N

    Therefore, the net force is 8761.5 N

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )