From what height must an oxygen molecule fall in a vacuum so that its kinetic energy at the bottom equals the average energy of an oxygen mo

Question

From what height must an oxygen molecule fall in a vacuum so that its kinetic energy at the bottom equals the average energy of an oxygen molecule at 300 K ?

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Khải Quang 3 years 2021-08-05T07:31:46+00:00 1 Answers 1 views 0

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  1. thnahdat
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    2021-08-05T07:33:35+00:00
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    Answer:

    The  value is  h = 11930 \ m

    Explanation:

    From the question we are told that

        The  temperature is  T = 300 \ K

         

    Generally the root mean square speed of the  oxygen molecules is mathematically represented as

            v = \sqrt{\frac{3 * R * T }{M} } = \sqrt{ 2 * g * h }

    Here  R is the gas constant with a value  R = 8.314 \ J\cdot K^{-1} \cdot \ mol^{-1}

        M  is the molar mass of oxygen molecule with value M = 0.032 \ kg /mol

    So  

         \frac{3 * 8.314 * 300 }{0.032} = 2 * 9.8 * h

    =>    h = 11930 \ m

       

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