Four equal-value resistors are in series with a 5 V battery, and 2.23 mA are measured. What isthe value of each resistor

Question

Four equal-value resistors are in series with a 5 V battery, and 2.23 mA are measured. What isthe value of each resistor

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Thiên Ân 5 years 2021-07-14T17:50:16+00:00 1 Answers 109 views 0

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  1. Sigrid
    0
    2021-07-14T17:51:36+00:00
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    Answer:

    560.54 Ω

    Explanation:

    Applying,

    V = IR’…………… Equation 1

    Where V = Voltage of the battery, I = currrent, R’ = Total resistance of the resistors

    make R’ the subject of the equation

    R’ = V/I………… Equation 2

    From the question,

    Given: V = 5 V, I = 2.23 mA = 2.23×10⁻³ A

    Substitute these values into equation 2

    R’ = 5/(2.23×10⁻³ )

    R’ = 2242.15 Ω

    Since the fours resistor are connected in series and they are equal,

    Therefore the values of each resistor is

    R = R’/4

    R = 2242.15/4

    R = 560.54 Ω

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