For a huge luxury liner to move with constant velocity, its engines need to supply a forward thrust of 7.80 105 N. What is the magnitude of

Question

For a huge luxury liner to move with constant velocity, its engines need to supply a forward thrust of 7.80 105 N. What is the magnitude of the resistive force exerted by the water on the cruise ship

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Nho 5 years 2021-09-05T12:07:35+00:00 1 Answers 42 views 0

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    2021-09-05T12:08:47+00:00

    Answer:

    F_{resistive}=7.80*10^{5}N

    Explanation:

    Given data

    Force_{thrust}=7.80*10^{5}N

    To find

    Magnitude of the resistive force

    Solution

    As from Newtons second law:

    When velocity is constant then  acceleration a=0

    So the magnitude of resistive force exerted by the water on the cruise ship

    is equal to the magnitude of forward thrust but the directions of forces are opposite(according to Newtons third law)

    So

    F_{resistive}-F_{thrust}=ma\\F_{resistive}-F_{thrust}=0\\Hence\\F_{resistive}=F_{thrust}\\F_{resistive}=7.80*10^{5}N  

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