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## First term / second mid Exam [1433/ 1434] Q12. A conductor of radius I, length and resistivity p has resistance R. What is the new resistanc

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## Answers ( )

Answer:R’ = 4R

Hence, the resistance increases to four times its initial value as well.

Explanation:The resistance of a conductor in terms of its physical dimensions can be given by the following formula:

_______ equation (1)

where,

R = Resistance of the conductor

ρ = resistivity of the material of the conductor

L = Length of the conductor

A = Cross-sectional Area of the conductor

Now, if the length of the conductor is increased to four times, keeping other values constant, then:

using equation (1):

R’ = 4RHence, the resistance increases to four times its initial value as well.