Find three consecutive odd integers such that the product of the first two is equal to one more than twice the third

Question

Question

in progress 0

Mathematics Neala 5 years 2021-07-29T07:02:01+00:00 2021-07-29T07:02:01+00:00 1 Answers 20 views 0

Answers ( )

Name*

E-Mail*

Website

Featured image

Browse

Captcha* Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )

Answer*

Eirian · Answer 1 · 2021-07-29T07:03:44+00:00

Eirian

0

2021-07-29T07:03:44+00:00 July 29, 2021 at 7:03 am

Reply

Answer:

$-3, -1, 1$ or $3, 5, 7$

Step-by-step explanation:

Let first consecutive odd integer = $x$

Second consecutive odd integer = $x+2$

Third consecutive odd integer = $x+4$

“Product of the first two is equal to one more than twice the third” can be written as:

$x(x+2)=1+2(x+4)$

$x^2+2x=1+2x+8$ (expand brackets)

$x^2+2x=9+2x$ (combine like terms)

$x^2=9$

$x=\pm3$

∴ Consecutive integers = $-3, -1, 1$ or $3, 5, 7$

Hope this helps 🙂