Find the value of n that makes DEF-XYZ when DE = 4, EF = 5, XY = 4(n + 1). YZ = 7n – 1, and

Question

Find the value of n that makes DEF-XYZ when
DE = 4, EF = 5, XY = 4(n + 1). YZ = 7n – 1, and

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Thu Giang 5 years 2021-08-30T16:55:44+00:00 1 Answers 31 views 0

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  1. thanhha
    0
    2021-08-30T16:57:30+00:00
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    Answer: n=3

    Step-by-step explanation:

    Understand that you need to set up a proportion before you can try to solve the question through guessing. In this case, YZ would be proportional to XY as EF is proportional to DE. You would write this as: EF/DE=YZ/XY.

    Now you want to write an equation. In order to do this remember to multiply by your proportion. Here’s my equation:

    5/4(4n+4)=7n-1. Now distribute:

    5n+5=7n-1. Now simplify:

    6=2n. Now simplify again:

    n=3

    Hope this helps you with your big ideas math hw!

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