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Find the inverse of g(n) = – 3 – 1 Og-1 (n) = -(n-3)-1 9 9-1 (n) = In g-1 (n) = (n + 1)3 + 3 Og-1 (n) = 3+n3<
Question
Find the inverse of g(n) = – 3 – 1
Og-1 (n) = -(n-3)-1
9
9-1 (n) = In
g-1 (n) = (n + 1)3 + 3
Og-1 (n) = 3+n3
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2021-09-05T07:58:43+00:00
2021-09-05T07:58:43+00:00 1 Answers
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Answers ( )
Answer:
[tex]g'(n) = -\frac{n+1}{3}[/tex]
Step-by-step explanation:
Given
[tex]g(n) = -3n – 1[/tex]
Required
Determine the inverse
[tex]g(n) = -3n – 1[/tex]
Replace g(n) with y
[tex]y = -3n – 1[/tex]
Swap positions of x and y
[tex]n = -3y – 1[/tex]
Make y the subject
[tex]3y = -n – 1[/tex]
[tex]3y = -(n + 1)[/tex]
[tex]y = -\frac{n+1}{3}[/tex]
Replace y with g'(n)
[tex]g'(n) = -\frac{n+1}{3}[/tex]