Find an equation of the line passing through the points (–3, –5) and (6, –2).

Question

Find an equation of the line passing through the points
(–3, –5) and (6, –2).

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Sapo 5 months 2021-08-15T03:25:25+00:00 2 Answers 9 views 0

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    0
    2021-08-15T03:26:37+00:00

    Answer: y=1/3x-4

    Explanation:

    Begin by finding the slope of the line. You can do this by using the given ordered pairs and plugging them into the slope formula, y^2-y^1/x^2-x^1. Plugging them would appear as -2-(-5)/6-(-3). The resulting math would be 3/9 or 1/3 when simplified. Using the slope-intercept form, we can plug in the slope to make it y=1/3x+b. Choose any ordered pair to plug into the equation. I’m going to use (-3,-5). Plugging this in would result with -5=1/3(-3)+b. Multiply 1/3 and -3 to get -5=-1+b. Add -1 to both sides to get b=-4.

    0
    2021-08-15T03:26:41+00:00

    Answer:

    y=1/3x-4

    Step-by-step explanation:

    1. Use the slope formula to find the slope of the two coordinates.

    y2-y1/x2-x1

    -2–5/6–3

    3/9 = 1/3

    The slope is 1/3

    2. Choose one of the coordinates and plug them and the slope into the point-slope formula

    y-y1=m(x-x1)

    y+2=1/3(x-6)

    3. Distribute and simplify.

    y+2=1/3x-2

    y=1/3x-4

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