fast ball with a velocity of 43 m/s south. The batter hits the ball and gives it a velocity of 51 m/s north. What was the acceleration of th

Question

fast ball with a velocity of 43 m/s south. The batter hits the ball and gives it a velocity of 51 m/s north. What was the acceleration of the ball if it was in contact with the bat for 1 s? What direction did it go?

PLEASE HELP I NEED THIS DONE FOR MY NEXT CLASS

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Khoii Minh 3 years 2021-07-16T00:27:48+00:00 1 Answers 7 views 0

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    2021-07-16T00:29:18+00:00

    Acceleration = (change in velocity) / (time for the change)

    change in velocity = (velocity after) – (velocity before)

    change in velocity = (51 m/s north) – (43 m/s south)

    that’s the same thing as (51 m/s north) + (43 m/s north)

    change in velocity = 94 m/s north

    Acceleration = (94 m/s north) / (1 second)

    Acceleration = 94 m/s² north

    The direction of the acceleration is North.

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