f an arrow is shot upward on the moon with velocity of 35 m/s, its height (in meters) after t seconds is given by h(t)=35t−0.83t 2. (a) Find

Question

f an arrow is shot upward on the moon with velocity of 35 m/s, its height (in meters) after t seconds is given by h(t)=35t−0.83t 2. (a) Find the velocity of the arrow after 3 seconds.

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Thu Cúc 4 years 2021-08-26T19:25:50+00:00 1 Answers 7 views 0

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  1. mit
    0
    2021-08-26T19:27:07+00:00
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    Answer:

    The velocity of the arrow after 3 seconds is 30.02 m/s.

    Explanation:

    It is given that,

    An arrow is shot upward on the moon with velocity of 35 m/s, its height after t seconds is given by the equation:

    h(t)=35t-0.83t^2

    We know that the rate of change of displacement is equal to the velocity of an object.

    v(t)=\dfrac{dh(t)}{dt}\\\\v(t)=\dfrac{d(35t-0.83t^2)}{dt}\\\\v(t)=35-1.66t

    Velocity of the arrow after 3 seconds will be :

    v(t)=35-1.66t\\\\v(t)=35-1.66(3)\\\\v(t)=30.02\ m/s

    So, the velocity of the arrow after 3 seconds is 30.02 m/s. Hence, this is the required solution.

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