f(x) = -1/2x^2 + 3/2x – 2 I need to find the zeros​

Question

f(x) = -1/2x^2 + 3/2x – 2 I need to find the zeros​

in progress 0
Thanh Hà 5 years 2021-07-15T14:09:18+00:00 1 Answers 18 views 0

Answers ( )

    0
    2021-07-15T14:10:19+00:00

    Answer:

    f(x) = -1/2x² + 3/2x – 2

    f(0) = (-1/2 × 0²) + (3/2 × 0) – 2

    f(0) = 0 + 0 – 2

    f(0) = -2

    THANK YOU!!( ◜‿◝ )♡

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )