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f(x) = -1/2x^2 + 3/2x – 2 I need to find the zeros
Question
f(x) = -1/2x^2 + 3/2x – 2 I need to find the zeros
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Mathematics
5 years
2021-07-15T14:09:18+00:00
2021-07-15T14:09:18+00:00 1 Answers
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Answer:
f(x) = -1/2x² + 3/2x – 2
f(0) = (-1/2 × 0²) + (3/2 × 0) – 2
f(0) = 0 + 0 – 2
f(0) = -2
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