En un proceso isobárico, la presión del gas es de 105 Pa. Halle el desplazamiento del pistón, cuya área es de 0,4 m2, cuando el gas desarrol

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En un proceso isobárico, la presión del gas es de 105 Pa. Halle el desplazamiento del pistón, cuya área es de 0,4 m2, cuando el gas desarrolla un trabajo de 8 x 104 J

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Thạch Thảo 5 years 2021-09-05T08:49:29+00:00 1 Answers 30 views 0

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  1. Nho
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    2021-09-05T08:50:59+00:00
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    Answer:

    The displacement of the piston is 1904.76 m

    Explanation:

    Here we have an isobaric or constant pressure process, therefore;

    Work done, W = P × (V₂ – V₁)

    Where:

    W = 8 × 10⁴ J

    P = Pressure of the gas = 105 Pa

    V₁ = Initial volume of the cylinder of the piston

    V₂ = Final volume of the cylinder of the piston

    We note that volume of the cylinder of the piston = Base area, A × h

    Therefore;

    V₁ = A × h₁

    V₂ = A × h₂

    Which gives;

    V₂ – V₁ = A × h₂ – A × h₁ = A×(h₂ – h₁)

    Where:

    A = Base area of the piston = 0.4 m²

    h₂ – h₁ = Displacement of the piston

    ∴ 8 × 10⁴ J = 105 Pa × (V₂ – V₁) = 105 Pa × 0.4 m² × (h₂ – h₁)

    h₂ – h₁ = (8 × 10⁴ J)/(105 Pa × 0.4 m²)

    h₂ – h₁ = 1904.76 m

    Hence the displacement of the piston = 1904.76 m.

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