## During the first 13 weeks of the television season, the Saturday evening 8:00 P.M. to 9:00 P.M. audience proportions were recorded as ABC 29

Question

During the first 13 weeks of the television season, the Saturday evening 8:00 P.M. to 9:00 P.M. audience proportions were recorded as ABC 29%, CBS 28%, NBC 25%, and independents 18%. A sample of 300 homes two weeks after a Saturday night schedule revision yielded the following viewing audience data: ABC 95 homes, CBS 65 homes, NBC 87 homes, and independents 53 homes. Test with = .05 to determine whether the viewing audience proportions changed.

Required:
Compute the value of the 2 test statistic (to 2 decimals). The p value is Has a significant change occurred in viewing audience proportions?

in progress 0
3 years 2021-08-21T02:04:44+00:00 1 Answers 114 views 0

– The value of the 2 test statistic is 6.98

– There is no sufficient evidence to reject the claim of the specific distribution

Step-by-step explanation:

Given

Proportion (p)

Samples

First, we formulate a table for chi square totals:

Where

O = Observed Frequency and E = Expected Frequency

So, we have:

For ABC

For CBS

For NBC

For others:

— approximated

The value of the 2 test statistic is 6.98

Next, is to determine the p value:

Calculate the degree of freedom

Using the table in the 3rd row,

corresponds to:

The value of p is:

This implies that, we fail to reject H o