Dos cargas con 2.8(×10-6) C y 7.5(×10-6) C respectivamente se atraen con una fuerza de 10 [N], ¿A qué distancia se encuentran separadas?

Question

Dos cargas con 2.8(×10-6) C y 7.5(×10-6) C respectivamente se atraen con una fuerza de 10 [N], ¿A qué distancia se encuentran separadas?

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Adela 5 years 2021-07-15T14:59:28+00:00 1 Answers 57 views 0

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  1. Vodka
    0
    2021-07-15T15:00:53+00:00
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    Answer:

    r = 0.137 m

    Explanation:

    The electric force is given by the Coulomb equation

              F = k q₁ q₂ / r²

    where k is the constant of Coulomb that is worth 8,988 10⁹ N m²/C², q₁ and q₂ are the charges and r is the distance that separates them

             r² = k q₁q₂ / F

             r = √ k q₁q₂ / F

    let’s calculate

             r = √ (8.99 10⁹ 2.8 10⁻⁶ 7.5 10⁻⁶⁶ / 10

             r = √ (1,8879 10⁻²)

             r = 0.137 m

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