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DF has midpoint E(1, -3). if ID(0, 2), what are the coordinates of F?
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DF has midpoint E(1, -3). if ID(0, 2), what are the coordinates of F?
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Mathematics
3 years
2021-08-18T15:53:50+00:00
2021-08-18T15:53:50+00:00 1 Answers
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Answer:
F is at (2, -8)
Step-by-step explanation:
use the midpoint formula: (sum of x-values/2, sum of y-values/2)
let (x,y) = coordinate of pt F
(0+x/2) = 1; x = 2
(2+y/2) = -3; 2 + y = -6; y = -8