Determine the rate at which the electric field changes between the round plates of a capacitor, 8.0 cm in diameter, if the plates are spaced

Question

Determine the rate at which the electric field changes between the round plates of a capacitor, 8.0 cm in diameter, if the plates are spaced 1.5 mm apart and the voltage across them is changing at a rate of 140 V/s .

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Vân Khánh 3 years 2021-08-28T12:56:53+00:00 1 Answers 20 views 0

Answers ( )

  1. thuthuy
    0
    2021-08-28T12:58:43+00:00
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    Explanation:

    It is known that the relation between electric field and potential difference between the plates of a parallel plate capacitor is as follows.

               E = \frac{V}{D}

    So, differentiating this on both the sides with respect o time as follows.

                \frac{dE}{dt} = \frac{1}{D} \frac{dV}{dt}

    Hence, rate of electric field changes between the plates of parallel plate capacitor as follows.

                \frac{dE}{dt} = \frac{1}{D} \frac{dV}{dt}

                     = \frac{1}{1.5 \times 10^{-3} m} \times 140 V/s

                     = 93.33 \times 10^{3} V/ms

    Thus, we can conclude that the rate at which the electric field changes between the round plates of a capacitor is 93.33 \times 10^{3} V/ms.

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