Determine the mass of 2.35 x 1024 molecules of Ca(NO3)

Question

Determine the mass of 2.35 x 1024 molecules of Ca(NO3)

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Khải Quang 5 years 2021-09-02T22:24:57+00:00 1 Answers 14 views 0

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  1. thnahdat
    0
    2021-09-02T22:26:09+00:00
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    Answer:

    2406.4 molecules of Ca(NO3)

    Explanation:

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )