determine the discount between the point(-4,2) and the line 4y=3×+6​

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determine the discount between the point(-4,2) and the line 4y=3×+6​

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Hồng Cúc 2 months 2021-08-01T04:37:06+00:00 1 Answers 2 views 0

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    2021-08-01T04:38:18+00:00

    Answer:

    d = 14/5

    Step-by-step explanation:

    The point (-4,2) means that;

    At x = -4, y = 2

    Now general form of a linear equation is;

    Ax + By + C = 0

    We are given;

    4y = 3x + 6​

    Rearranging to the form of a linear equation gives;

    3x – 4y + 6 = 0

    Thus, A = 3, B = -4 and C = 6

    Thus, at point (-4,2), distance between them is;

    d = (3(-4) – 4(2) + 6)/√(3² + (-4)²)

    d = -14/5

    We will take the absolute value.

    Thus; d = 14/5

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )