Describe the motion of a particle with position (x,y) as t varies in the given interval. x=3sint, y=1+cost, 0≤t≤3π/2

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Describe the motion of a particle with position (x,y) as t varies in the given interval. x=3sint, y=1+cost, 0≤t≤3π/2

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Thanh Thu 1 week 2021-07-22T11:10:10+00:00 1 Answers 1 views 0

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    2021-07-22T11:11:10+00:00

    Answer:

    The motion is centered about (0,1)

    Step-by-step explanation:

    x = 3sint —- (1)

    y = 1 + cos(t) —– (2)

    x^2 = 9 *sin(t)*sin(t)  

    hence; (x^2)/9 = sin(t)*sin(t) —- (3)

    y-1 = cos(t)  

    hence; (y-1)^2 = cos(t) * cos(t)  —- (4)

    adding  equation 3 and 4

    (x^2)/9 + ( y – 1 )^2 = 1

    The motion is centered about (0,1)

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