Crossed electric and magnetic fields are established over a certain region. The magnetic field is 0.669 T vertically downward. The electric

Question

Crossed electric and magnetic fields are established over a certain region. The magnetic field is 0.669 T vertically downward. The electric field is 2.64 x 106 V/m horizontally east. An electron, traveling horizontally northward, experiences zero net force from these fields and so continues moving in a straight line. What is the electron’s speed

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Ngọc Hoa 3 years 2021-07-17T13:51:14+00:00 1 Answers 22 views 0

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    2021-07-17T13:52:24+00:00

    Answer:

    The speed  is v = 3.946 *10^6 \ m/s

    Explanation:

    From the question we are told that

         The magnetic  field is  B =  0.669\ T

          The electric field is  E = 2.64 *10^{6} \ V/m

         

    Generally the speed of the electron is mathematically represented as

                   v = \frac{E}{B}

        Substituting values

                    v = \frac{2.64 *10^6}{0.669}

                    v = 3.946 *10^6 \ m/s

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