Convert 4.97 x 10′ grams of ammonia (NH3) to moles of ammonia.

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Convert 4.97 x 10′ grams of ammonia (NH3) to moles of ammonia.

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Thiên Hương 5 years 2021-08-18T05:54:03+00:00 1 Answers 13 views 0

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  1. Amity
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    2021-08-18T05:55:27+00:00
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    Answer: There are 0.292 \times 10^{-4} mol are present in 4.97 \times 10^{-4} g of ammonia.

    Explanation:

    Given: Mass of ammonia = 4.97 \times 10^{-4} g

    As number of moles is the mass of substance divided by its molar mass.

    Hence, moles of ammonia (molar mass = 17 g/mol) are calculated as follows.

    No. of moles = \frac{mass}{molar mass}\\= \frac{4.97 \times 10^{-4} g}{17 g/mol}\\= 0.292 \times 10^{-4} mol

    Thus, we can conclude that there are 0.292 \times 10^{-4} mol are present in 4.97 \times 10^{-4} g of ammonia.

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