Consider the system consisting of the box and the spring, but not Earth. How does the energy of the system when the spring is fully compress

Question

Consider the system consisting of the box and the spring, but not Earth. How does the energy of the system when the spring is fully compressed compare to the energy of the system at the moment immediately before the box hits the ground? Justify your answer.

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Adela 3 years 2021-08-11T04:42:11+00:00 1 Answers 3 views 0

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  1. Doris
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    2021-08-11T04:43:15+00:00
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    Answer:

    the energy when it reaches the ground is equal to the energy when the spring is compressed.

    Explanation:

    For this comparison let’s use the conservation of energy theorem.

    Starting point. Compressed spring

             Em₀ = K_e = ½ k x²

    Final point. When the box hits the ground

             Em_f = K = ½ m v²

    since friction is zero, energy is conserved

              Em₀ = Em_f

              1 / 2k x² = ½ m v²

              v = \sqrt{ \frac{k}{m} }     x

    Therefore, the energy when it reaches the ground is equal to the energy when the spring is compressed.

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