Consider the quadratic equation x? = 4x – 5. How many solutions does the equation have? A The equation has one real solution. The equation h

Question

Consider the quadratic equation x? = 4x – 5. How many solutions does the equation have? A The equation has one real solution. The equation has two real solutions. The equation has no real solutions. D The number of solutions cannot be determined​

in progress 0
Euphemia 6 months 2021-07-17T08:31:30+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-17T08:32:35+00:00

    Answer:

    {-1, 5} (two real solutions).

    Step-by-step explanation:

    On the left side we want x^2, not x?

    We need to rewrite x? = 4x – 5 in standard form, that is, as a quadratic with x terms in decreasing powers of x:

    x^2 – 4x + 5 = 0

    This factors easily to (x – 5)(x + 1) = 0.

    We let each factor equal zero (0) separately and solve for x:  

    {-1, 5} (two real solutions).

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )