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## Consider the quadratic equation x? = 4x – 5. How many solutions does the equation have? A The equation has one real solution. The equation h

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Consider the quadratic equation x? = 4x – 5. How many solutions does the equation have? A The equation has one real solution. The equation has two real solutions. The equation has no real solutions. D The number of solutions cannot be determined

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Mathematics
6 months
2021-07-17T08:31:30+00:00
2021-07-17T08:31:30+00:00 1 Answers
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## Answers ( )

Answer:{-1, 5} (two real solutions).

Step-by-step explanation:On the left side we want x^2, not x?

We need to rewrite x? = 4x – 5 in standard form, that is, as a quadratic with x terms in decreasing powers of x:

x^2 – 4x + 5 = 0

This factors easily to (x – 5)(x + 1) = 0.

We let each factor equal zero (0) separately and solve for x:

{-1, 5} (two real solutions).