Consider the quadratic equation x? = 4x – 5. How many solutions does the equation have? A The equation has one real solution. The equation h

Question

Consider the quadratic equation x? = 4x – 5. How many solutions does the equation have? A The equation has one real solution. The equation has two real solutions. The equation has no real solutions. D The number of solutions cannot be determined​

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6 months 2021-07-17T08:31:30+00:00 1 Answers 0 views 0

{-1, 5} (two real solutions).

Step-by-step explanation:

On the left side we want x^2, not x?

We need to rewrite x? = 4x – 5 in standard form, that is, as a quadratic with x terms in decreasing powers of x:

x^2 – 4x + 5 = 0

This factors easily to (x – 5)(x + 1) = 0.

We let each factor equal zero (0) separately and solve for x:

{-1, 5} (two real solutions).