## Consider an oblique shock wave with a wave angle equal to 35-degrees. Upstream of the wave, P1 = 2000 lb/ft2, T1 = 520-degrees R, and V1 = 3

Question

Consider an oblique shock wave with a wave angle equal to 35-degrees. Upstream of the wave, P1 = 2000 lb/ft2, T1 = 520-degrees R, and V1 = 3355 ft/s. Calculate P2, T2, V2, and the flow deflection angle.

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3 years 2021-08-23T05:23:01+00:00 1 Answers 124 views 0

P2 The pressure is 6570  lbf/ft²

T2 The temperature is 766 ⁰R

V2 The velocity is 2746.7 ft/s

flow deflection angle is 17.56⁰

Explanation:

Speed of air at initial condition:

γ is the ratio of specific heat,

R is the universal gas constant,

T is the initial temperature.

initial mach number

then

based on the values obtained, read off the following from table;

P₂/P₁ = 3.285

T₂/T₁ = 1.473

Mₙ₂ = 0.6355

Thus;

P₂ = 3.285P₁

= 3.285(2000)

= 6570  lbf/ft²

T₂ = 1.473T₁

= 1.473(520⁰R)

= 766 ⁰R

We determine the velocity and deflection angle, first we calculate the mach number.