Consider a closed circuit with a 9-volt battery connected in series to a light bulb with a resistance of 3 ohms. What is the current flowing

Question

Consider a closed circuit with a 9-volt battery connected in series to a light bulb with a resistance of 3 ohms. What is the current flowing through the light bulb?

in progress 0
Eirian 3 years 2021-08-26T05:12:04+00:00 2 Answers 7 views 0

Answers ( )

  1. huyenthanh
    0
    2021-08-26T05:13:48+00:00
    Reply

    Answer:

    current flowing through the light bulb = 3A

    Explanation:

    current= voltage divided by Resistance

    I = V/R

    Given that,

    resistance = 3 ohms

    V = 9 volt

    current = 9 volt /  3 ohms

    = 3A

    current flowing through the light bulb = 3A

  2. mit
    0
    2021-08-26T05:13:56+00:00
    Reply

    Answer:

    Current flowing through the light bulb = 3 Amps

    Explanation:

    Since the light bulb is a resistive load, it can obey ohm’s law

    Voltage across the battery, V = 9 volts

    Resistance of the light bulb, R = 3 ohms

    According to Ohm’s law, V = IR

    I = V/R

    I = 9/3

    I = 3 Amps

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )