RI SƠ 154 Questions 856 Answers 1 Best Answer 25 Points View Profile0 RI SƠ Asked: October 14, 20202020-10-14T01:44:41+00:00 2020-10-14T01:44:41+00:00In: Môn ToánChứng tỏ rằng x^2=-10x+26>0 với mọi x0Chứng tỏ rằng x^2=-10x+26>0 với mọi x ShareFacebookRelated Questions Tìm số abc a. 1abc + abc x 12 - abc3 = 1372 b. abc x 7 = a0bc ( không ... giả sử chỉ có biết hình bình hành là tứ giác có cặp cạnh đối ngang, các em hãy chứng ... Tìm x ∛2x-1 +1= 2x So sánh ∛5√2 và √5∛2 ...2 AnswersOldestVotedRecentDâu 160 Questions 851 Answers 0 Best Answers 20 Points View Profile Dau 2020-10-14T01:45:51+00:00Added an answer on October 14, 2020 at 1:45 am `x^2-10x+26``=x^2-10x+25+1``=x^2-2.x.5+5^2+1``=(x-5)^2+1` $\geq$ `1`(vì `(x-5)^2` $\geq$ `0 ∀x`)0Reply Share ShareShare on FacebookNem 171 Questions 788 Answers 0 Best Answers 27 Points View Profile Nem 2020-10-14T01:46:03+00:00Added an answer on October 14, 2020 at 1:46 am Đáp án: `x^2 – 10x + 26``= x^2 – 10x + 25 + 1``= x^2 – 5x – 5x + 25 + 1``= (x^2 – 5x) – (5x – 25) + 1``= x(x – 5) – 5(x – 5) + 1``= (x – 5)(x – 5) + 1``= (x – 5)^2 + 1`Do `(x – 5)^2 ≥ 0 => (x – 5)^2 + 1 ≥ 1 > 0`Giải thích các bước giải: 0Reply Share ShareShare on FacebookLeave an answerLeave an answerCancel reply By answering, you agree to the Terms of Service and Privacy Policy .* Save my name, email, and website in this browser for the next time I comment.
Dâu
`x^2-10x+26`
`=x^2-10x+25+1`
`=x^2-2.x.5+5^2+1`
`=(x-5)^2+1` $\geq$ `1`
(vì `(x-5)^2` $\geq$ `0 ∀x`)
Nem
Đáp án:
`x^2 – 10x + 26`
`= x^2 – 10x + 25 + 1`
`= x^2 – 5x – 5x + 25 + 1`
`= (x^2 – 5x) – (5x – 25) + 1`
`= x(x – 5) – 5(x – 5) + 1`
`= (x – 5)(x – 5) + 1`
`= (x – 5)^2 + 1`
Do `(x – 5)^2 ≥ 0 => (x – 5)^2 + 1 ≥ 1 > 0`
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