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Chuck’s car is moving at 65.0m/s when he suddenly accelerates his car at 15.0m/s2 for 3.00s. How far did Chuck, and his car, travel while he
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Answers ( )
Answer:
x = 265.5 m
Explanation:
To find the distance traveled by the car you first use the following formula:
(1)
vo: initial velocity = 65.0m/s
a: acceleration = 15.0m/s^2
t: time = 3.00 s
you replace the values of vo, t and a in the equation (1) in order to calculate the final velocity v:
= 110 m/s
Next, you use the following formula:
x: distance traveled
You do x the subject of the formula and replace the values of vo, v and a:
hence, the distance traveled by the car is 265.5 m