Chameleons catch insects with their tongues, which they can rapidly extend to great lengths. In a typical strike, the chameleon’s tongue acc

Question

Chameleons catch insects with their tongues, which they can rapidly extend to great lengths. In a typical strike, the chameleon’s tongue accelerates at a remarkable 210 m/s^2 for 20 ms, then travels at constant speed for another 30 ms.
During this total time of 50 ms, 1/20 of a second, how far does the tongue reach?
Express your answer to two significant figures and include the appropriate units.

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Thành Đạt 3 years 2021-08-13T18:50:57+00:00 1 Answers 19 views 0

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    2021-08-13T18:52:32+00:00

    Answer:

      x_total = 0.17m

    Explanation:

    We can treat this exercise with the kinematics equations, where in the first part it is accelerated and in the second it is a uniform movement.

    Let’s analyze accelerated motion

    The time that lasts is t = 20 10⁻³ s, the initial speed is zero (v₀ = 0), let’s find the length that advances

                x₁ = v₀ t + ½ a t²

                x₁ = ½ a t²

                x₁ = ½ 210 (20 10⁻³)²

                x₁ = 4.2 10⁻² m

     

    let’s find the speed for the end of this movement

                v = v₀ + a t

                v = 0 + 210   20 10⁻³

                v = 4.2 m / s

    with this speed we can find the distance that the uniform movement

               x₂ = v t2

               x₂ = 4.2   30 10⁻³

               x₂ = 1.26 10⁻¹ m

               x₂ = 0.126m

    the total distance traveled is

              x_total = x₁ + x₂

              x_total = 0.0420 +0.126

              x_total = 0.168m

               

         Let’s reduce the significant figures to two

              x_total = 0.17m

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