Cau a bai 1 va cau a bai 2. Question Cau a bai 1 va cau a bai 2. in progress 0 Môn Toán Dulcie 5 years 2021-05-22T15:15:27+00:00 2021-05-22T15:15:27+00:00 1 Answers 24 views 0
Answers ( )
Đáp án:
`A={3+\sqrt{3}}/6`
`P=-3-2\sqrt{3}`
Giải thích các bước giải:
Bài 1
`a)` `A=1-{\sqrt{x}}/{\sqrt{x}+1}` $(x\ge 0)$
`A={\sqrt{x}+1-\sqrt{x}}/{\sqrt{x}+1}`
`A=1/{\sqrt{x}+1}`
Ta có: `x=7-4\sqrt{3}`
`<=>x=2^2-2.2.\sqrt{3}+3`
`<=>x=(2-\sqrt{3})^2`
`<=>\sqrt{x}=2-\sqrt{3}`
`=>A=1/{2-\sqrt{3}+1}=1/{3-\sqrt{3}}`
`<=>A={3+\sqrt{3}}/{(3-\sqrt{3}).(3+\sqrt{3})}`
`<=>A={3+\sqrt{3}}/{3^2-3}={3+\sqrt{3}}/6`
$\\$
Bài 2
`a)` ` x=4-2\sqrt{3}`
`<=>x=3-2.\sqrt{3}.1+1`
`<=>x=(\sqrt{3}-1)^2`
`<=>\sqrt{x}=\sqrt{3}-1`
$\\$
`P={\sqrt{x}+1}/{\sqrt{x}-1}` $(x\ge 0; x\ne 1)$
`P={\sqrt{3}-1+1}/{\sqrt{3}-1-1}`
`P={\sqrt{3}}/{\sqrt{3}-2}`
`P={\sqrt{3}.(\sqrt{3}+2)}/{(\sqrt{3}-2).(\sqrt{3}+2)}`
`P={3+2\sqrt{3}}/{3-4}`
`P=-3-2\sqrt{3}`