Share
Calculate the specific heat of a metal from the following data. A container made of the metal has a mass of 3.8 kg and contains 20 kg of wat
Question
Calculate the specific heat of a metal from the following data. A container made of the metal has a mass of 3.8 kg and contains 20 kg of water. A 2.3 kg piece of the metal initially at a temperature of 165°C is dropped into the water. The container and water initially have a temperature of 15.0°C, and the final temperature of the entire system is 18.0°C.
in progress
0
Physics
3 years
2021-08-30T02:10:11+00:00
2021-08-30T02:10:11+00:00 1 Answers
0 views
0
Answers ( )
Answer:
C = 771.35 J/kg°C
Explanation:
Here, e consider the conservation of energy equation. The conservation of energy principle states that:
Heat Given by Metal Piece = Heat Absorbed by Water + Heat Absorbed by Container
Since,
Heat Given or Absorbed by a material = m C ΔT
Therefore,
m₁CΔT₁ = m₂CΔT₂ + m₃C₃ΔT₃
where,
m₁ = Mass of Metal Piece = 2.3 kg
C = Specific Heat of Metal = ?
ΔT₁ = Change in temperature of metal piece = 165°C – 18°C = 147°C
m₂ = Mass of Metal Container = 3.8 kg
ΔT₂ = Change in temperature of metal piece = 18°C – 15°C = 3°C
m₃ = Mass of Water = 20 kg
C₃ = Specific Heat of Water = 4200 J/kg°C
ΔT₃ = Change in temperature of water = 18°C – 15°C = 3°C
Therefore,
(2.3 kg)(C)(147°C) = (3.8 kg)(C)(3°C) + (20 kg)(4186 J/kg°C)(3°C)
C[(2.3 kg)(147°C) – (3.8 kg)(3°C)] = 252000 J
C = 252000 J/326.7 kg°C
C = 771.35 J/kg°C