Calculate the number of moles of iron (III) oxide (Fe 2 O 3 ) produced from 112 L of oxygen (O 2 ) in the following reaction

Question

Calculate the number of moles of iron (III) oxide (Fe 2 O 3 ) produced from 112 L of oxygen
(O 2 ) in the following reaction

4Fe(s) + 3O2 (g) = 2Fe2O3 (s)

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Thu Nguyệt 5 years 2021-08-29T17:31:06+00:00 2 Answers 21 views 0

Answers ( )

  1. RobertKer
    0
    2021-08-29T17:32:17+00:00
    Reply

    Answer:

    3.33 moles is the required answer.

    Explanation:

    4Fe+3O_2\Rightarrow \:2Fe_2O_3

    We’re going to use proportion to find the number of moles of iron oxide.

    \frac{\:3\:}{2}\:=\:\frac{\mathrm{Actual\:\text{No}.\:of\:moles\:of\:O_2}}{\mathrm{\text{Actual No}.\:of\:moles\:of\:Fe}_2O_3\:}\:

    Actual no. of moles of oxygen = \frac{112}{22.4}   (Since one mole at STP = 22.4 L)

    = 5

    Putting the values in the proportion.

    \frac{\:3\:}{2}\:=\:\frac{5}{x}\:\\\\x=3.33\:\mathrm{moles\:of\:Fe_2O_3}

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  2. thanhcong
    0
    2021-08-29T17:32:23+00:00
    Reply

    112 L/ 16 L = 7 mol O2

    7 mol O2 x 2 mol Fe2O3/ 3 mol O2 = 4.67 mol Fe2O3

    lmk if its right

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