Calculate the mass in grams of Potassium Nitrate (KNO3) to make 300.0 mL of a 0.020 M solution?

Question

Calculate the mass in grams of Potassium Nitrate (KNO3) to make 300.0 mL of a 0.020 M solution?

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Vân Khánh 5 years 2021-08-22T12:08:56+00:00 1 Answers 23 views 0

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  1. thuthuy
    0
    2021-08-22T12:10:21+00:00
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    Answer:

    0.606 g of KNO₃.

    Explanation:

    We’ll begin by converting 300 mL to L. This can be obtained as follow:

    1000 mL = 1 L

    Therefore,

    300 mL = 300 mL × 1 L / 1000 mL

    300 mL = 0.3 L

    Next, we shall determine the number of mole of KNO₃ in the solution. This can be obtained as follow:

    Volume = 0.3 L

    Molarity of KNO₃ = 0.020 M

    Mole of KNO₃ =?

    Mole = Molarity x Volume

    Mole of KNO₃ = 0.020 × 0.3

    Mole of KNO₃ = 0.006 mole.

    Finally, we shall determine the mass of 0.006 mole of KNO₃. This can be obtained as follow:

    Mole of KNO₃ = 0.006 mole.

    Molar mass of KNO₃ = 39 + 14 + (16×3)

    = 39 + 14 + 48

    = 101 g/mol

    Mass of KNO₃ =?

    Mass = mole × molar mass

    Mass of KNO₃ = 0.006 × 101

    Mass of KNO₃ = 0.606 g

    Thus, 0.606 g of KNO₃ is needed to prepare the solution.

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